ARITHMETIC PROGRESSION (AP)
Arithmetic progression in which the difference between the consecutive term is constant.
In other words the next term is calculated by adding a fixed number in the previous term. This fixed term is called common difference.
For example:
3,6,9,12.....is an arithmetic progression because the common difference is same i.e. ⟦ 6-3=9-6=12-9=3⟧
General representation of AP:
a,a+d,a+2d,a+3d.........
Here a is called the first term and d is the common difference.
nth term= a+(n-1)d
Arithmetic mean= sum of terms of AP/No of terms of AP
Sum of AP (S)=n/2⟦2a+(n-1)⟧d
If the a is first term and T is the last term then
Sum of AP (S)=n/2⟦a+T⟧
Example:
1. Find the nth term of 1,3,5,7.....
nth term=a+(n-1)d
=1+(n-1)2
Example:
1. Find the nth term of 1,3,5,7.....
nth term=a+(n-1)d
=1+(n-1)2
=1+2n-2
nth term=2n-1
2. Find the 10th term of 2,4,6,8,10...
for this sequence a=2
and common difference=2
nth term=a+(n-1)d
10th term=2+(10-1)2
=2+9*2
10th term =20
3.Find the no of term in the 8,12,16..........72
for this sequence a=8
and common difference=4
No. of term=(l-a)/d+1
=(72-8)/4+1
=64/4+1
=16+1
=17
No of term=17
4. Find 3+7+11+15.....+20 terms
For this a=3
and common difference=4
Sum= n/2⟦2a+(n-1)⟧d
=20/2[2*3+(20-1)]4
=10[6+19]4
=40*25
Sum =1000
nth term=2n-1
2. Find the 10th term of 2,4,6,8,10...
for this sequence a=2
and common difference=2
nth term=a+(n-1)d
10th term=2+(10-1)2
=2+9*2
10th term =20
3.Find the no of term in the 8,12,16..........72
for this sequence a=8
and common difference=4
No. of term=(l-a)/d+1
=(72-8)/4+1
=64/4+1
=16+1
=17
No of term=17
4. Find 3+7+11+15.....+20 terms
For this a=3
and common difference=4
Sum= n/2⟦2a+(n-1)⟧d
=20/2[2*3+(20-1)]4
=10[6+19]4
=40*25
Sum =1000
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