Monday, August 13, 2018

LOGARITHMS

LOGARITHMS

The logarithms of any number of a given base is equal to which the base should be raised to obtain the given number.

We write "the number of 2s we need to multiply to get 8 is 3" as:
log2(8) = 3

then this is read as "log base 2 of 8 is 3"

PROPERTIES OF LOGARITHMS:

  • logx+logy=log(xy)
  • logx-logy=log(x/y)
  • {\displaystyle \log _{b}\left(x^{p}\right)=p\log _{b}x}
  • {\displaystyle \log _{b}{\sqrt[{p}]{x}}={\frac {\log _{b}x}{p}}}
  • {\displaystyle \log _{b}x={\frac {\log _{k}x}{\log _{k}b}}.\,}
  • logb b = 1
  • logb 1 = 0

Example:

If logx+logy=log(x+y) then find the relation between x and y.
⇒logx+logy=log(x+y)
or
⇒log(xy)=log(x+y)
or
⇒xy=(x+y)

Example:

If  logx+log(4x)=log4 then find the value of x?
⇒logx+log(4x)=log4
⇒logx+log(4x)=log4
⇒log(4x²)=log4
⇒4x²=4
⇒x²=1
⇒x=±1
from this x=-1 and x=1
but x=1 is the only solution because negative of log is not defined.

Example:

If  logx-log(4)=log2 then find the value of x ?
⇒logx-log(4)=log2
⇒logx-log(4x)=log4
⇒log(x/4)=log4
⇒(x/4)=4
⇒x=16

What is the value of log₆ (1296)?

let y=log61296
y=log664
y=4log66
y=4log6/log6
y=4

Work for you
1. Find x, if log2x+logx=log8
2. Find the relation between x,y and z, if 2logx+logy=logz
3. Find x, if 2logx-log4=log4





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