FIND THE PARTIAL FRACTION OF (x+14)/(x-4)(x+2)
(x+14)/(x-4)(x+2)=a/(x-4)+b/(x+2).......1.
Simplify (1/16x)+(1/8)) / ((1/4)+(1/8x))?
(x+14)/(x-4)(x+2)=⟦a(x+2)+b(x-4)⟧(x-4)(x+2)
or
(x+14)=⟦a(x+2)+b(x-4)⟧
put
x=-2
-2+14=⟦a(-2+2)+b(-2-4)⟧
12=b(-6)
b=-2
and
put
x=4
4+14=⟦a(4+2)+b(4-4)⟧
18=6a
a=3
hence
from 1.
(x+14)/(x-4)(x+2)=3/(x-4)-2/(x+2)
((1/16x)+(1/8)) / ((1/4)+(1/8x)) =y assume y=N/D
N=numerator=((1/16x)+(1/8))
and
D=(1/4)+(1/8x)
N=((1/16x)+(1/8))=
Now solve this
N=(1+2x)/16x
and
D=(1/4)+(1/8x)
D=(2x+1)/8x
Now y=N/D=(1+2x)/16x/(2x+1)/8x=8x/16x=1/2
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