Sunday, August 5, 2018

DIFFERENTIATION AND DERIVATIVE


What is the d/dx x^tanx?

y=x^tanx
taking log on both side
⇒logy=log(x^tanx)
or
⇒logy=tanx.logx
⇒differentiate both side
⇒(1/y)y’=tanx.(1/x)+logx.sec^2x
⇒y’={tanx/x+(logx.sec^2x)}*y
y’={tanx/x+(logx.sec^2x)}*x^tanx
What is  

This function can be written as
y=xy
take log on both sides
logy=logxy
logy=ylogx
diffentiate on both sides
1/y(dy/dx)=y/x+logx(dy/dx)
dy/dx(1/y-logx)=y/x

dy/dx=(y/x)/(1/y-logx)
What is the value of the derivative of log (base a) x?

y=logax
y=logx/loga
dy/dx=(1/x)/loga

dy/dx=logae/x



What is the differentiation of ?

y=ln(sinxcosx) 
using chain rule
dy/dx=1/(sinxcosx) d/dx(sinxcosx)
dy/dx=1/(sinxcosx)((sinx(-sinx)+cosx(cosx))
dy/dx=(cos²x-sin²x)/(sinxcosx) 
dy/dx=cos2x/(sinxcosx)




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